H0:

H1: , for some j=0,1,2,3,4

We need to test this model make sense or not by doing an analysis of variance.

        If H0 is accepted, all  are equal to zero, then there are no relationship between y, X1, X2, X3 and X4. If H0 is rejected, then the model makes sense.    Therefore, it is meaningful to do the forward selection, backward elimination and stepwise selection to get the best model.

 

Analysis of Variance( ANOVA table)11

 

 

 

Source

DF

Sum of square

Mean square

F-value

Pr>F

Model

4

2158.73

539.68

4.07

0.0184

Error

16

2122.22

132.64

 

 

Corrected Total

20

4280.95

 

 

 

From the above table, we see that the model with all four variables is acceptable.

Since the p-value from ANOVA table is 0.0184 which is smaller than 0.05